使用JavaScript函数实现高效扑克牌排序技巧

18 min read

可以按照扑克牌的权值大小(从小到大)和花色(从小到大)进行排序,具体实现可以使用以下的函数:

def sort_cards(cards):
    mapping = {
        'A': 14,
        'K': 13,
        'Q': 12,
        'J': 11,
        'T': 10
    }
    # 将字母转化为数字
    for i, card in enumerate(cards):
        if card[0] in mapping:
            cards[i] = (mapping[card[0]], card[1])
        else:
            cards[i] = (int(card[0]), card[1])
    # 排序
    cards.sort()
    # 将数字转化为字母
    for i, card in enumerate(cards):
        if card[0] == 14:
            cards[i] = ('A', card[1])
        elif card[0] == 13:
            cards[i] = ('K', card[1])
        elif card[0] == 12:
            cards[i] = ('Q', card[1])
        elif card[0] == 11:
            cards[i] = ('J', card[1])
        elif card[0] == 10:
            cards[i] = ('T', card[1])
        else:
            cards[i] = (str(card[0]), card[1])
    return cards

这个函数将扑克牌列表作为输入,返回一个按照权值大小和花色进行排序的列表。它将字母(A、K、Q、J、T)转化为数字,然后排序,最后再将数字转化为字母。